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  1. #1
    Raider of the lost time
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    e minus to nu W minus then


    After ionization of deuterium atoms, it is not wise to throw away all those electronic leptons, analogous to a brewing tea party and reading fortunes from the tea leaves afterward. The corresponding elementary particle annihilations and creations are electrons to electron-neutrinos and W-minuses then these electron-neutrinos are annihilated creating brand new species of electrons and W-pluses.

    High energy physics does not forbid the transformation of electrons into electron-neutrinos and W-minuses. Everyone at CERN would no doubt concur. On the other hand, the same people would not doubt that in turn these produced electron-neutrinos would retransform back into electrons and W-pluses. The trick of getting something out of nothing (quantum vacuum) seems to work according to plan. The plan is to trap enough W-pluses and W-minuses (to be exact these vector gauge bosons ratio is 4 W-pluses and 2 W-minuses) for initialization of one of the few options for cold fusion nuclear reaction. Incidentally, the inventor of WD-40 took the 40th try before he was successful http://en.wikipedia.org/wiki/WD-40. Hopefully, displacements of vacuum by W-pluses and W-minuses would take less than 40 years. Coincidently, Noah’s flood also took 40 days and 40 nights to subside.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
    Green Belt
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    Re: e minus to nu W minus then

    Does the electron need to be given extra energy by accelerators to transform into electron-neutrinos and W-minuses or does the creation of vacuum energy occur randomly at statistically the same rate as its destruction? If this process really does violate the law of conservation of energy, are there any other ways?

  3. #3
    Raider of the lost time
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    Re: e minus to nu W minus then

    The outcome could be called a nuclear democracy that no elementary particles is more fundamental relative to any other particles.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 

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