If double conjugations can be implemented to space-time charges at the local as well as nonlocal infinitesimal region of the space-time continuum then the question is how can triple conjugation be implemented also? It can be stated without proof that the rate of triple conjugation gives the physical equivalence of lightspeed. Theoretically, any even multiples can be implemented. For examples: 1 H-plus and 1 H-minus, 2 H-pluses and 0 H-minus, 3 H-pluses and 1 H-minus, 5 H-pluses and 1 H-minus. As noted, the total numbers of H-pluses and H-minuses must be even: 1+1=2, 2+0=2, 3+1=4, 5+1=6, so on and so forth.

For successful conjugations containing odd numbers of H-pluses and H-minuses the results are called fermions. For even numbers the results are called bosons. Clearly, these do not require supersymmetric descriptions. However, any triple space-time charge configuration can conjugate along two binary operations of mass matrix multiplication and charge matrix addition. There are four distinct combinations: 3 H-pluses, 3 H-minuses, 2 H-pluses and 1 H-minus, 1 H-plus and 2 H-minuses. Any two within each group of three can conjugate at a time, say, between H-plus and H-plus, H-plus and H-minus, or H-minus and H-minus. Respectively, the results are 2 mass H-pluses and 2 charge H-pluses, 2 mass H-minuses and zero charge, 2 mass H-pluses and 2 charge H-minuses. Then these conjugate with the one remaining space-time charge in each group of three giving two photons in opposite directions. The transition speed between the first and the second conjugation is equal to the vacuum speed of light. The caveat is that only space-time charges of the same physical dimension can participate in every step of double or triple conjugation. The physical dimensions are equivalent to the size of the corresponding Hadamard matrices representing the space-time charges as squares of energy of the quantum vacuum fluctuations of zero-point energies.