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Thread: antideuteron
- 12-08-2011, 11:06 AM #21Raider of the lost time
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Re: antideuteron
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-08-2011, 11:29 AM #22Moderator
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Re: antideuteron
Yes indeed pass on to those in need.
Originally Posted by AntonioLao 
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-08-2011, 11:54 AM #23Raider of the lost time
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Re: antideuteron
But the insecurity of the needy can make them greedy.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-08-2011, 12:05 PM #24Moderator
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Re: antideuteron
It can,but let's hope that with better education this will not happen. Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-08-2011, 12:16 PM #25Raider of the lost time
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Re: antideuteron
But where are the selfless educators to do just that?
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-08-2011, 12:24 PM #26Moderator
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Re: antideuteron
Now that is a good question,Where indeed! Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-09-2011, 10:42 AM #27Raider of the lost time
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Re: antideuteron
Somehow self-motivated people can well educate themselves. All successful people in any enterprise are basically self-motivated. Many rich people never finish high school.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-09-2011, 10:47 AM #28Moderator
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Re: antideuteron
Yes I too have heard of this,you have tto be self motivated and have one pointed vision. Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
- 12-09-2011, 11:04 AM #29Raider of the lost time
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Re: antideuteron
But in solving a problem of physics, the means, the motive, and the opportunity must be established.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-09-2011, 11:07 AM #30Moderator
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Re: antideuteron
Yes you must have a base line on which to start. Originally Posted by AntonioLao
regards michael.Humilty,coupled with boldness,surprises truth to
reveal herself?
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