But not equally lateral as in equilateral?
But not equally lateral as in equilateral?
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Both squares and equilateral triangles can tessellate the totality of the space-time continuum but the triangles are more compact.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
That is why the strong nuclear force is the strongest of all fundamental forces.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
It means compactness also is happening in the distribution of the quanta of the space-time continuum.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
That is the way of nature's economy. Natural forces always follow the path of least resistance. Analytical mechanics (also used by quantum mechanics) called this the Lagrangian energy function guided by a principle of least action. In a quantum theory of the space-time continuum, this is replaced by a principle of double least action and the conserved physical quantity is the square of energy as the difference of square of kinetic energy and square of potential energy.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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