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  1. #1
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    Was there a Fleischmann-Pons fusion?

    In 1989, the controversy found in Fleischmann-Pons fusion is its claim of a radioactiveless form of energy production. On the other hand, by conventional nuclear physics, the two radiative forms of nuclear reactions are: (1) deuterium plus deuterium give Helium-3 plus neutron, and (2) deuterium plus deuterium give tritium plus proton. The first has its radiation given off as fast (or slow) neutrons. The second has its radiation given off by radioisotope of hydrogen called tritium, which has a radioactive tendency of losing one of its two neutrons. However, by taking into consideration the idea of two electrons number balancing, the first reaction indicates both electrons capture by the Helium-3 since no free neutron can capture either one of the two electrons because of the inherent electric neutrality of the free neutron. This free neutron (fast or slow) can give off a 15-minute radiation by its decay into a proton, an electron, and an electron neutrino. Consequently, one proton and one electron can form one atom of ordinary hydrogen. The second reaction gives radioactive tritium and ordinary hydrogen with both products sharing one electron. This tritium product is capable of losing one of its two neutrons. This free neutron can then decay by the same process mentioned previously.


    In contrast, the controversial Fleischmann-Pons fusion suggested the third kind of nuclear interaction by the following reaction that deuterium plus deuterium give Helium-4 plus excess energy. This excess energy has the probable expected value equivalent to the binding energy of an alpha particle. This is not a coincidence since like Helium-4; each alpha particle also has the same nucleon number: two protons and two neutrons. Again, by electron number balancing, it is very clear that Helium-4 captured both electrons and the excess energy is equivalent to the expected binding energy of an alpha particle given by experiments with the statistical value of 28.3 MeV. By a quantum theory of the space-time continuum, this value could be used to represent the maximum energy extractable from the quantum vacuum for each pair of deuterons for cold fusion.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Re: Was there a Fleischmann-Pons fusion?

    The Alpha particle sounds like something we need.


    regards michael.
    Humilty,coupled with boldness,surprises truth to
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  3. #3
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    Re: Was there a Fleischmann-Pons fusion?

    But the problem is to catch it if you can since alpha particles are fast moving particles as one of the three products of all radioactivities. The other two products are beta radiation and gamma radiation, respectively, fast moving electrons and energetic photons.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
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    Re: Was there a Fleischmann-Pons fusion?

    Quote Originally Posted by AntonioLao View Post
    But the problem is to catch it if you can since alpha particles are fast moving particles as one of the three products of all radioactivities. The other two products are beta radiation and gamma radiation, respectively, fast moving electrons and energetic photons.
    That does then pose a real problem.


    regards michael.
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  5. #5
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    Re: Was there a Fleischmann-Pons fusion?

    Since alphas are electrically charged they can be deflected using very strong magnet. This magnet must be strong enough to deflect them around a completely circular chamber. Adding electrons to this chamber will definitely produce helium gas and maybe some excess energies of cold fusion.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
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    Re: Was there a Fleischmann-Pons fusion?

    Quote Originally Posted by AntonioLao View Post
    Since alphas are electrically charged they can be deflected using very strong magnet. This magnet must be strong enough to deflect them around a completely circular chamber. Adding electrons to this chamber will definitely produce helium gas and maybe some excess energies of cold fusion.
    You make it sound easy,but I guess it is really very difficult.

    regards michael.
    Humilty,coupled with boldness,surprises truth to
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  7. #7
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    Re: Was there a Fleischmann-Pons fusion?

    It is difficult only in finding financial backing.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  8. #8
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    Re: Was there a Fleischmann-Pons fusion?

    Quote Originally Posted by AntonioLao View Post
    It is difficult only in finding financial backing.
    It will get even worse in this global crisis.

    regards michael.
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  9. #9
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    Re: Was there a Fleischmann-Pons fusion?

    But if any able person contributed $1 to the cause of deuteron cold fusion, how mcuh can we collect?
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  10. #10
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    Re: Was there a Fleischmann-Pons fusion?

    Quote Originally Posted by AntonioLao View Post
    But if any able person contributed $1 to the cause of deuteron cold fusion, how mcuh can we collect?
    About 50000 dollars if we were lucky.


    regardsmichael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

 

 
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