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About LinkBacksSimilar to the Hilbert space of quantum mehanics, Hadamard space is a vector space of two outer products or cross products or vector products then the inner product of these products give square of energy.
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Thread: introduction to Hadamard space
- 10-18-2005 04:35 PM #1Raider of the lost time
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introduction to Hadamard space
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 10-18-2005 05:15 PM #2The Thinker
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Can you give me the equation for that?
It's that I find it much easier in equations, the thing is that in language it looks like a lot of words saying nothing.
- 10-18-2005 05:41 PM #3Raider of the lost time
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It is in the introduction to the paper on Hadamard matrices dated October 11, 2005.
Originally Posted by GUILLE Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 10-19-2005 05:51 PM #4The Thinker
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What page? Originally Posted by AntonioLao
- 10-20-2005 12:44 PM #5Raider of the lost time
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If you cant find it on page 1 then I'm going to write the latex equation here
[Unparseable Latex Formula]Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 10-21-2005 06:05 PM #6The Thinker
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Can't see the latex equation in your post. But I did find it in the paper. Thanks. Originally Posted by AntonioLao
- 10-23-2005 03:21 PM #7Raider of the lost time
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As the classifications of several known algebraic structures, the special Hadamard matrices used for spacetime quantization are all classifiable as semigroups with only the property of associativity for both operations of addition and multiplication. Although these special types of Hadamard matrices are not invertible (zero determinants), there still exist unique zero matrices as the identities of addition. The advantage of these special Hadamard matrices over other algebraic structures is their commutative property under the operations of both addition and multiplication.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
- 12-09-2007 01:04 AM #8Master
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Re: introduction to Hadamard space
Antonio;
Could you please provide a link to the paper that you mention here. I notice you talk of these Hadamard matrices quite often, so I'd like to get more of a feel for them.~neutralino
If you haven't found something strange during the day, it hasn't been much of a day - John A. Wheeler.
- 12-17-2007 04:31 PM #9Raider of the lost time
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Re: introduction to Hadamard space
I'll try to recover the file I made about Hadamard matrices which was lost from the url site. Merry Christmas and a Happy New Year! Originally Posted by neutralino Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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