| Fermi fusion -
12-27-2005, 01:35 PM
The most promising fusion reaction to date giving energy output per helium nucleus of 17.6 MeV is the deuterium-tritium combination. The plasma of positive deuterons, positive tritons, and negative electrons need their initial relative velocities high enough to breakaway the Coulomb potential barrier. However, fusion cannot occur unless the mean free path limit is set above 1 fermi and no more than 3 fermis. The difference of 2 fermis is the effectiveness of attractive strong nuclear force. Below 1 fermi the strong force is repulsive. Above 3 fermis it is practically zero. To reach the free path limit, a quadruple magnetic field is the ideal configuration with 2 sets of conjugate B-fields, one external and one internal. All of these can be individually controlled such that the radii of gyration approach within 2 fermis and the conjugates capable of giving positive and negative magnetic helicities. For second order perturbation, the electric and magnetic moments of the proton, neutron, and electron need detailed considerations. During the process, the neutrons must remain bound to the D-T nuclei. Nevertheless, one neutron will eventually be set free and if not captured within 15 minutes, it decays into another proton, another electron, and a neutrino. Still, it remains fuzzy whether the Fermi length could be derived from double time integrations given constant electric current with specific ion mass such that the integrand is the cross product of a radius vector and the magnetic field vector.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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Linear Mode
