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About LinkBacksI know this stuff, I've been immersed in these theories for two decades now. Trust me, I know about the gauge symmetry group theory and all of that.
I'm saying that I "discovered" quarks and protons and all of that while trying to work out how you could tie a knot in space. Naturally I wasn't the first person to find them, but it was just something that emerged from my relativistic ponderings, and another reason I say everything is Simply Relativity.
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Thread: CERN's LHC
- 09-18-2008 02:45 PM #218th degree Black Belt
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Re: CERN's LHC
Emily: Has anyone really been far even as decided to use even go want to do look more like?
Stage Manager: No. *pauses* The physicists and mathematicians, maybe they do some.
- 09-18-2008 02:59 PM #22Raider of the lost time
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Re: CERN's LHC
Max,
You sure are the luckies toequester I ever know for knowing things people been trying to understand. If you can explain it clearly and maybe help me build the ultimate cold fusion reactor then that would be one way to show that your theory is the correct one. The problem with cold fusion is to allow two deuteron nuclei to get close enough for them to change into a Helium-4 nucleus plus excess energy. And it is a fact that the deuteron is made of 3 up quarks and 3 down quarks a total of 12 quarks configuration of the He-4.Time independence: [∂E(g)]˛=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c˛
- 09-18-2008 06:05 PM #238th degree Black Belt
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Re: CERN's LHC
You misunderstood my post.
I said that I am well versed in quantum mechanics, QED, fairly well acquainted with QCD, String Theory, M-Theory, Matrix Theory, SR, GR, and all sorts of iterations of those theories.Emily: Has anyone really been far even as decided to use even go want to do look more like?
Stage Manager: No. *pauses* The physicists and mathematicians, maybe they do some.
- 09-19-2008 12:45 PM #24Raider of the lost time
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Re: CERN's LHC
The important thing to consider is their interconnections.
Time independence: [∂E(g)]˛=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c˛
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