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11-09-2005, 05:43 PM
Who can answer the question? As we know only one side of the Moon is always visible, but the second – so called “Dark side of the Moon” is never seen from the Earth! If it is remembered that the Moon spins on its own axis (besides spinning around the Earth), then we can say that the axis of the Moon always remains vertical to the surface of the Earth. Is it really so? And why it happens? | |
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11-10-2005, 03:09 PM
I think it's to do with the centre points of gravity. Definatelly it is to do with acceleration, mass and distance.
But there is something I know, and I didn't kno wuntil very little time ago, and it is that the earth and the moon also move around a point between the two, not in the middle, but nearer to the earth, because it's to do with the mass. So actually it's not exactly how the diagram says, there is another rotation, done by the two, around this point which is probably in earth, around where planes fly, I estimate, due to the masses. | |
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12-04-2005, 06:48 AM
I hoped somebody from physicists would answer my question...
I'm asking again, please answer, is really the axis of the Moon always vertical to the Earth's surface? | |
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12-04-2005, 12:42 PM
Quote: |
Originally Posted by <<>> I think it's to do with the centre points of gravity. Definatelly it is to do with acceleration, mass and distance.
But there is something I know, and I didn't kno wuntil very little time ago, and it is that the earth and the moon also move around a point between the two, not in the middle, but nearer to the earth, because it's to do with the mass. So actually it's not exactly how the diagram says, there is another rotation, done by the two, around this point which is probably in earth, around where planes fly, I estimate, due to the masses. | I've heard that Jupiter and the Sun do the same thing, although the point at which they rotate around is located under the surface on the sun. | |
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12-04-2005, 12:57 PM
Quote: |
Originally Posted by zeroca I hoped somebody from physicists would answer my question...
I'm asking again, please answer, is really the axis of the Moon always vertical to the Earth's surface? | Zeroca;
Relative to the Sun, the Moon make one rotation of its axis for every lunar cycle.
The axis of a sphere is linear, the surface of the Earth is not and thus you cannot have a vertical relationship between a linear property to a curved property. You can only have a tangent to a point on the Earth at any given time. Since the Earth is tilted on its axis, the axes are not parallel either.
What is your purpose of such a question?
You can project a vertical line between the centers of gravity if you like. David | |
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12-05-2005, 12:41 AM
Dave! Excuse me, under the term “Earth’s surface” I meant tangential plane to a point on the Earth at any given time. You know I’m not scientist and try to explain some regularities of universe for myself, so I need exact knowledge (known facts) from others, who knows it better than me (thus I avoid wasting of time on searching this material without success), so I need to know the cause, regularity why pair Earth-Moon behaves this way. As you know I believe that planets aren’t attracted to each other, but the matter is striving to the centers of planets, in adjacent spaces of which it’s placed, so I try to solve it on the example of pair Earth-Moon, but all seems very vague so far… Projecting of a vertical line between the Axes (centers of gravity?) that of the Earth and that of the Moon would have been possible, if the axes had been placed on parallel planes. If axes had been parallel, or placed on parallel planes, the Moon wouldn’t have had “dark side” (invisible side from the Earth), so they’re either vertical or tilted to each-other, or angle between them changes every time according to some order, i.e. anyway they're tilted to each-other. Even if they’re tilted to each-other, the imaginable equator of the Moon must remain parallel with tangential plane to a point on the Earth at any given time. Anyway I’d like to understand clearly why it happens…
Regards,
Merab
Last edited by Robert : 12-08-2005 at 03:01 AM.
Reason: added changes as requested by poster
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12-25-2005, 03:02 PM
I’d like to repeat the post, which was published by me before: Choose a fine weather and look up to the sky. If you see a little white cloud on the blue sky you must be sure that its linear speed is the same as that of its shade on the surface of the Earth beneath the cloud, i.e. it’s over 1600 km/hour (Over 460 m/sec) if the cloud is on the equator… Who can say that the cloud (amount of water steam) is moving with such a high speed and doesn’t change its form (shape) for some period of time (for several minutes)? That’s unbelievable!!! But this little white cloud in fine weather almost doesn’t move relatively to the surface of the Earth for this period of time, i.e. it’s staying at rest towards it (and towards neighboring little clouds as well), i.e. we have to acknowledge that the part of space, adjacent to the Earth – where the little white cloud is placed for a while, is spinning with the speed of cloud, (i.e. the space and little white cloud are spinning together (along with the surface of the Earth beneath them), i.e. the cloud is at rest towards the space and the surface of the Earth… I.e. the space is bind to planet and spins along with it (i.e. the space adjacent to the planet inherits the momentum of the planet, too)… Yes, and in this case the cloud has the opportunity to stay unmoved relatively to the Earth and to its adjacent space, and at the same time to spin with the speed of the Earth’s surface relatively to the center of the planet, like a passenger in the car, who’s moving with the speed of the car relatively to the surface of the Earth, but is staying at rest relatively to the car itself, i.e. According to this analogy cloud is a passenger of the space-body (which’s unity of heavenly body with its adjacent space), i.e. the cloud is a passenger of space, which is spinning with the Earth together. Animation: If we are looking at the spinning of the Earth form North or South Pole: Each turn lasts for 24 hours... Upper cloud: "The cloud is a passenger of space, which is spinning with the Earth together"... Nether cloud: If the space hadn’t turned along with the Earth on the axis of it, the little white cloud in fine weather would have always moved to the west with the speed of over 1600km/hour relatively to the surface of the Earth, i.e. it would have fallen behind to spinning of the Earth with mentioned speed... The plane of screen is counted as a plane of ecliptic, approximately. | |
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12-25-2005, 03:05 PM
As we mentioned in a previous post, it’s obvious that the space adjacent to the Earth spins along with the planet. The second and the most interesting fact is that the space above the poles and the space above the equator spin differently. The difference is shown in animation below: The linear speed of the white cloud above the equator is more than 1600km/hour, i.e. over 460 m/sec, but of the white cloud above the pole is too low; I.e. the space, adjacent to the equator, (i.e. above-equator part of the space, adjacent to the Earth) spins with very high speed, but the above-pole part of it – with very low speed. I have another question: Does the orbit (a circle), circumscribed by the Moon around the Earth, lie on the plane of Earth’s equator, on the plane of Earth’s meridian, or is tilted to them with angle, or the Moon doesn’t describe the “fixed” circle around the Earth and the angle between the Earth’s equator’s plane and the Moon’s orbit is changing every time? | |
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12-25-2005, 06:01 PM
Quote: |
Originally Posted by zeroca Does the orbit (a circle), circumscribed by the Moon around the Earth, lie on the plane of Earth’s equator, on the plane of Earth’s meridian, or is tilted to them with angle, or the Moon doesn’t describe the “fixed” circle around the Earth and the angle between the Earth’s equator’s plane and the Moon’s orbit is changing every time? | The orbit circumscribed by te moonaround the earth lies on the whole of earth as a gravitational atraction. The centre parts of the earth, as they have a bigger space, they have a higher mass, so they occupy more of the determination of the orbit. Whiles the poles as there is very little depth compared to the centre, then it doesn't occupy as much of the orbit order. So the idea is: the circumference in a chosen longitude is taken to determine the amount of mass in the whole of that line knowing the avarage mass in the inner part of the earth, we determine the mass there: divided by the mass of the whole earth, and you know how much it is of the whole in fraction. Then you have to apply newton's gravitation formula and there you get the gravity that zone atracts to the moon. Then you divide this for the whole of earth (which is 9.8N) and see how much it occupies of the atraction. Probably of course tha angle does have importance for the distance between the moon and parts of the earth is different... Too many variables if what you want is to calculate.
I just remembered that the title of this thread is the title of a one of the best albums made by Pink Floyd ever. I remember the lyrics of some songs:
The lunatics are in my hall
The paper holds their folded faces to the floor
And every day the paper boy brings more
And if the dam breaks open many years too soon
And if there is no room upon the hill
And if your head explodes with dark forbodings too
I'll see you on the dark side of the moon
.................. | |
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12-28-2005, 01:37 PM
Hey, Guille, twenty years from now you will still crank up the volume to that music, so enjoy. You are on the track of a lifetime. Ah, to see the next generation fall into the same great music, makes me nostalgic. | |
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