Did you send me a paper with this result?Originally Posted by AntonioLao
Could you send it to me?
Did you send me a paper with this result?Originally Posted by AntonioLao
Could you send it to me?
This is something I have also done, but to an accuracy of three decimal places. The full explanation is in my book, but the final equation for the mass ration of the proton to electron is:Originally Posted by AntonioLao
2^5*pi^3*Phi^2/sqrt(2)
I have a web page that briefly describes the number as well.
http://www.16pi2.com/particle_gap_number.htm
Dave
I'll send it at a later date since it needs reprocessing.Originally Posted by GUILLE
I'll look at your calculation more carefully at a later date. Similarly, I did have a factor of square root of 2 but the other factors are from matrix multiplication of H+ and H-, which are singular matrices (determinants are zero).Originally Posted by volantis
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Antonio,
Let me know when you are going to send it (I don't always check my e-mail).
Volantis,
I read the small page you gave linked to, but, my question arises:
Do you have an explenation about why each figure and operation is where it is?
I could send you part of it at the latest by end of this week. This coming Sunday.Originally Posted by GUILLE
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Paolo Budinich wrote a theory of everything and published it.Originally Posted by volantis
See hep-th/0311045 "Internal Symmetry from Division Algebras
in Pure Spinor Geometry".
Even though he is a member of the physics community, nobody has
accepted what he wrote.
If you would like to read the original paper go here:
http://www.imath.kiev.ua/~snmp2003/Proceedings/budinich.pdf
David![]()
Why do you think this is then?Originally Posted by thomas cuny
Is there a valid reason that you could think of.Maybe his idea was too
off beam for them?
kind regard michael.
Humilty,coupled with boldness,surprises truth to
reveal herself?
There are currently 1 users browsing this thread. (0 members and 1 guests)