Domain of relativistic mechanics

[07PRADEEP]

dear steve,

i appreciate your effort to explain the concept to me. But i am still skeptical about what you told regarding light speed. I have learned that light speed is similar to any established law of physics in that it remains constant no matter what the observer's speed is or where he is located. Also i have learned that even gravity waves travel at the same speed and that space-time warps in order to accommodate this limiting factor. Now if light photon can travel at infinite speed, how do we explain the warping of space-time?

Pleasant

well numbertheory cannot be absurd.

[07PRADEEP]

I feel, in essence,that I should present a comprehensive,unambiguous and unequivocal view of the Domain of Relativistic Mechanics.Domain of Relativistic Mechanics:
One needs to have ,a great knowledge of Inequalities(part of mathematics-algebra),to scrutinize relativisticmechanics and understand the crux of its deficiency.Let us probe






TIME DILATON EQUATION



t = t′
√ (1― v²/c²)




where t′ is the time measured in S′ frame is slower than the time
measured t in inertial frame S by time dilation equations.In all these cases, c stands for velocity of light and equal to it.,whereas v is the velocity of the frame S′ with respect to S.
On rearranging the relativistic equation ,simplifies to( t′c)²=(tc )²―(tv)²,which finally leads to (t′)²=(t)²―( tv/c)²


We proceed like this:At this stage,my invented formula’s most simplified form will be adequate in proving my contention. A simpler form of my formula could be treated as ,the formula 4AB= (A+B)² ― ( A ― B)²,when we apply(N-1)=A and X=B which on further simplification leads to
AB=[(A+B)/2 ]² ― [ ( A ― B)/2]² by rearranging.,will thereby have the merits and advantages of my formula , which is worth mentioning.
Since in reality,
( A+B)/2>(A―B)/ 2 because t > (tv/c) in all cases.Therefore B>0.
We are going to check whether the numerical values are satisfied or how number theory can help in our endeavor.Let us assume above simple algebraic formula is analogous to (t′)²=(t)²―( tv/c)² [called standard equation, hereafter,to signify relativistic equation for convenience] where t′ in L.H.S represents (measured) time in frame S ′,further in the standard equation
, quantities in R.H.S have their usual conventions and meanings.
Only case considered.Case – 1 Let A = k, B = (k― 2 tv/c.)Since B< A ,further at some instance, B could be the above variable value proposed (variable behaviour is not restrained), for a grander understanding of matters, and in no case violates the essentials or fundamentals of any science,since k can assume any value.The equation becomes
(k)(k―2 tv/c)=(k―tv/c)²― (tv/c)² [ hereafter referred to as considered equation is invented algebraic formula modified.],we get (tv < ck/2) , (tv<ck) ergo,tv<ck/2 is the deduction,since B>0 .It should be noted t′<k is also observed here, by virtue of comparisons[between equations,standard and considered].Also analogous comparisons leads to t < k [between equations and second terms of them or first terms in R.H.S ]where k stands for any fixed value,(albeit,it(k) can assume any value) .Therefore, final inference is maximum of v equal to c/2 units by virtue of maximum of t=k.Excuse me to have prejudged it.The sequence of steps to result in that is.Step 1, Since (tv < ck/2) , (tv<ck)conclusion is(tv < ck/2)should be considered here,because B>0.Step 2 You have to..compare [between equations and third terms or second terms in R.H.S ] between tv/c which becomes kv/c,from standard equation since maximum of t=k. and the most significant part ie tv/c which leads to k/2 in the considered equation ,that ought to be proved now. Since maximum of tv/c=(ck/2)(1/c), which leads to tv/c=k/2,since c gets cancelled from both numerator and denominator,hence, great leap of conclusion resulting is maximum of v=c/2 units.Note, in the previous step, the criterion tv<ck/2 has been utilised in the considered equation,hence maximum of tv=ck/2.Also,note you are equating tv/c which is atmost equal to kv/c in the standard equation with tv/c which is atmost equal to k/2 in the considered equation,thereby to obtain the result.Step3 : Maximum of kv/c=k/2,implies maximum of v=c/2 units,after cancelling out k from both sides.




Conclusion:

Maximum of v=c/2 units, in RELATIVISTIC MECHANICS DOMAIN namely Case - 1 Case -1 tv<kc/2 , t′ time in frame S′, t′ element of 0 to k seconds and t<k seconds,
Where k stands for any fixed value ,however large in seconds.



In case 1 not only numerical verification is done by number theory developed by me, even if ,units and dimensions are considered as issues,will not hamper the
conclusion.