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    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    moment 2 inertia

    The moment the universe came into being inertia was created. Moment of inertia is to mass as angular motion is to linear motion. Both were used to describe some aspect of uniform motion. Therefore without uniform motion, both linear and angular motions could not exist, consequently, nor inertial mass and gravitational mass. In order for the universe to exist, first and foremost, there must be uniform motion.

    In physics, the conventional symbol for the moment of inertia is capital letter ( I ) and it is equal to the product sum of mass elements with each moment arm distance from a given axis of circular motion: I=∫mr. Since torque ( t ) is defined as the product of I and the angular acceleration ( a ), and furthermore, the product of a and ( R ) where R is the vector sum of all squares of the moment arm distances: R = ∫r therefore t is equal to the product of m and a and R: t = amR. However, the angular acceleration is also defined as the ratio of tangential acceleration ( a ) over R: a = a/R, hence t = maR if and only if vector division is clearly defined. But ma is simply the inertial force ( F ). Finally, in order to agree with conventional definition the torque is then the vector product of F and R: t = F´R. Furthermore, the scalar product of two-torques is defined as the square of energy: E = F´R × F´R.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
    Moderator mkirkpatrick has much to be proud of mkirkpatrick has much to be proud of mkirkpatrick has much to be proud of mkirkpatrick has much to be proud of mkirkpatrick has much to be proud of mkirkpatrick has much to be proud of
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    Smile Re: moment 2 inertia

    Uniform motion,now that's something to think about?



    regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?


 

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