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extrinsic curvature
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extrinsic curvature - 11-28-2005, 08:21 PM

Quote:
Originally Posted by GUILLE
But it is yet a finite measurement, easilly to find: 2xpixr
This is fine if we live outside the 1 dimensional circle and r is the extrinsic curvature.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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11-29-2005, 03:36 AM

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Originally Posted by AntonioLao
This is fine if we live outside the 1 dimensional circle and r is the extrinsic curvature.
I know, but what I mean is that the quantity that we ahve of circle is always finite, even though you can go round and round for ever. The fact that you can go around forever has nothing to do with the infinity of the circle, in fact, it, in any case, would prove time is eternal, but nothing about the circle itself.
  
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1d circle - 11-29-2005, 11:39 AM

circle is defined in 1 dimension if and only if the intrinsic curvature exists. Furthermore, this curvature must be capable of visualization by the 1D beings. We are having the same kind of problem visualizing the 4D intrinsic curvature of Einstein's 4D spacetime.


Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²
  
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