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  1. #1
    Raider of the lost time
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    dof, entropy, and LIM

    In TQS (theoretical quantum space-time), one fundamental assumption is that a local infinitesimal motion (LIM) exists. This is the localized oscillation of a space-time point in term of its zero-point angular frequency ω°. If ω°=0 then the minimum number of degrees of freedom (dof) is six. If ω°>0 then the minimum is eight. Macroscopically, the dof is unbounded and space-time approaches a continuum.

    When dof=8 space-time is both mass and time independence. When dof=6 space-time is only time independence. When dof is greater than 8 then space-time is both time and mass dependence.

    Using H+ and H-, the dofs are directed lines segments pointing outward or pointing inward. Ideally, all dofs point inward for H- and point outward for H+ as shown by the image below:



    If entropy is related to ω° then since ω°≥ 0 implies that entropy can never be less than zero.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #2
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    Smile

    Quote Originally Posted by AntonioLao
    In TQS (theoretical quantum space-time), one fundamental assumption is that a local infinitesimal motion (LIM) exists. This is the localized oscillation of a space-time point in term of its zero-point angular frequency ω°. If ω°=0 then the minimum number of degrees of freedom (dof) is six. If ω°>0 then the minimum is eight. Macroscopically, the dof is unbounded and space-time approaches a continuum.

    When dof=8 space-time is both mass and time independence. When dof=6 space-time is only time independence. When dof is greater than 8 then space-time is both time and mass dependence.

    Using H+ and H-, the dofs are directed lines segments pointing outward or pointing inward. Ideally, all dofs point inward for H- and point outward for H+ as shown by the image below:



    If entropy is related to ω° then since ω°≥ 0 implies that entropy can never be less than zero.
    But Antonio.is there anything less than zero!
    kindest regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  3. #3
    Raider of the lost time
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    yes and no

    Quote Originally Posted by mkirkpatrick
    is there anything less than zero!
    Directionally speaking, yes as in positive and negative direction. Magnitude-wise, no. But financial institutions like banks and saving and loan, they allow your money accounts going below less than zero.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #4
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    Smile less than zero costs money!

    Quote Originally Posted by AntonioLao
    Directionally speaking, yes as in positive and negative direction. Magnitude-wise, no. But financial institutions like banks and saving and loan, they allow your money accounts going below less than zero.
    You are so right Antonio,but there is a hefty interest charged for the privilge.
    kindest regards michael.
    Humilty,coupled with boldness,surprises truth to
    reveal herself?

  5. #5
    Raider of the lost time
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    hidden charges

    Quote Originally Posted by mkirkpatrick
    but there is a hefty interest charged for the privilge.
    And some hidden charges such as transaction fee, deposite/withdrawal fee, access fee, overnight fee, ATM fee, etc.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  6. #6
    The Thinker
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    Antonio,

    then as angular momentum is it means that the energy of a space-time quanta when a particle goes through it is times the distance interval. Is this equation (as it icludes the square of energy) in harmony with your equations?

  7. #7
    Raider of the lost time
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    zero momentum

    Quote Originally Posted by GUILLE
    Is this equation...in harmony with your equations?
    must be zero in order to establish time independence. Although it properly describes photons when they are not able to interact among themselves.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

 

 

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