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Thread: spin fusion

  1. #31
    Raider of the lost time AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold AntonioLao is a splendid one to behold
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    Re: spin fusion

    Quote Originally Posted by G_burnett
    varied effecting in the chemistry disciplines
    Quantum vacuum displacements is similar to Norm Larsen's water displacements for his invention of WD-40 see link http://en.wikipedia.org/wiki/WD-40 and my new thread on 'e minus to nu W minus then'. I will work on a budget plan for an experimental pilot study of its feasiblity.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  2. #32
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    Re: spin fusion

    I am under the impression that the spin of a released neutron is there but not rotation such as an axle rotation event, more of a random rotation state of spinear in the mental construct. Needing then direction of motion induced....

    Thus comes to a ponder that the enrichment of ion nature in the cold is lost by the reel in the primary as the encompasing causal. Two streams in the torus comes to mind in reverse motion or angular release possible in the cyclic.

    but then once more this morn sees me here without my hot coffee.

    kind regards, graham

  3. #33
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    Re: spin fusion

    From high energy particles perspective the neutron is a composite of 1 up quark and 2 down quarks. All are 1/2 integer spin particles. Therefore their symmetric rotation axis must be 720 degrees.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  4. #34
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    Re: spin fusion

    Quote Originally Posted by AntonioLao View Post
    From high energy particles perspective the neutron is a composite of 1 up quark and 2 down quarks. All are 1/2 integer spin particles. Therefore their symmetric rotation axis must be 720 degrees.
    I Antonio;

    I'm a little confused, well more than a little, but would ( Does ) the neutron revolve ( spin ) arounds it's axis like a gyroscope? Also why 2 full turns, why not 1 and half?

    Best,

    Pat

  5. #35
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    Re: spin fusion

    Quote Originally Posted by AntonioLao View Post
    From high energy particles perspective the neutron is a composite of 1 up quark and 2 down quarks. All are 1/2 integer spin particles. Therefore their symmetric rotation axis must be 720 degrees.
    Interesting road.

    ...do you think they have an order of exist on an axial symmetry or individual axle rotation in symmetry for a conjoin .. no lets say combined unit? (Not a trick question knowing the varied shape in V define.)

    Kind regards graham

  6. #36
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    Re: spin fusion

    As a fermion of 1/2 integer spin the neutron can be describe using Dirac theory of the spinors. Since spin is quantized it is a 2-valued quantum numbers, say top or bottom or left or right or front or back. Where and when mapped into a non-orientable Mobius surface 720 degrees is required for the rotational invariance.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

  7. #37
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    Re: spin fusion

    The presentation of Dirac theory in first or second quantization in Physics and the discipline of math make use of the covariant spinier fields. The Hestenes define is being proven incorrect to use the addition muti-vector or homogeneous fields addition to conflicts with the Fierz identities.

    This is quite the contentious subject right now out there.

    It may be a barrier?

    kind regards graham

  8. #38
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    Re: spin fusion

    Although Pauli's spin matrices and Dirac spinor matrices have inverses and whose squares equal the corresponding identity matrix of 2 by 2 or 4 by 4, they are all non-commutative requiring a non-Abelian ring topology. On the other hand, spacetime charges of Hadamard matrix algebra is a commutative double Abelian ring topology. Unfortunately, symmetric Hadamard matrices have zero determinant hence no inverses. But this could be a blessing in disguise and make spacetime charges unique in certain sense, that is to say H+ and H- are not topologically equivalent, one cannot be transformed into the other, vice versa.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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    G_burnett (03-13-2010)

  10. #39
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    Re: spin fusion

    ... how do you envision the H+ H- regards transient nature of state .. in motion with direction from the sours and decay to potential in singularity of position... and thus do we consider the source causal of motion enough?
    Would thus the source give us the predictable?

    One may not be able to be transformed into the other once established in motion but maybe before in the static potential v = 0, p = 1 state the motive force could do to one thus being only the manner of measure platform .. IMHO g
    Last edited by G_burnett; 05-09-2009 at 04:53 PM. Reason: spell

  11. #40
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    Re: spin fusion

    The commutative algebra of H+ and H- for this ring topology is that in the same LOE adding H+ and H- gives the zero matrix. Multiply H+ and H- gives H- and multiply H+ and H+ or H- and H- gives H+.
    Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

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