vacuum compressibility

AntonioLao · **vacuum compressibility -** 05-16-2005, 11:26 AM

as indicated by the equation of continuity of hydrodynamics, when the source term $\sigma$ is zero, the vanishing of the divergence is a necessary and sufficient condition that the fluid in becoming incompressible and also its divergence is equal to the density.

$\frac{1}{\rho}\frac{d\rho}{dt}+\nabla\cdot \mathbf{v} - \sigma = 0$

but the equation is derivable based on the validity of the following 3D Cartesian total and partial derivatives:

$\frac{d\rho}{dt}=\frac{\partial \rho}{\partial x}\frac{\partial x}{\partial t} + \frac{\partial \rho}{\partial y}\frac{\partial y}{\partial t}+ \frac{\partial \rho}{\partial z}\frac{\partial z}{\partial t}+ \frac{\partial \rho}{\partial t}$

the total time derivative of density is the sum of the changes at the point (x, y, z) and the rate at which the fluid at this point is flowing to other parts of the field where the density is different.

A vacuum glass chamber can be artificially created by the use of a vacuum pump. It can be demonstrated that light can pass thru the chamber from one side to the other showing that light or electromagnetic waves are not hindered by the existence of a vacuum. Experimentally, the speed of light inside the chamber is ~186,000 miles per second, while its speed outside the chamber of normal air pressure is less. This implies that the compressibility of any vacuum is indicated by speed of light in that particular vacuum.

AntonioLao · 05-17-2005, 01:30 PM

Quote:

Originally Posted by quanta07

I believe this is the property of expansion/contraction.....

but what happens when the rate of expansion equals the rate of contraction? Does time stop ticking at this equilibrium point?

Guille · 05-17-2005, 01:37 PM

Quote:

Originally Posted by AntonioLao

but what happens when the rate of expansion equals the rate of contraction? Does time stop ticking at this equilibrium point?

I think that the moment of equilibrium will be that: a moment. A very short period of time, so small, that there will be no time to distenguish: it will be the smallest "quanta" of time, so time will not pass, I think. Although time will re-activate inmediatelly after.

AntonioLao · 05-17-2005, 01:40 PM

As gauge by the speed of light, my main question for starting this post is what is the maximum compression (contract) or expression (explode) allowable for degree of emptiness of the vacuum? why the value of light speed has to be what it is. Does higher values for light speed indicate a much more emptier vacuum? What is the meaning of absolute emptiness? In absolute emptiness, the speed of light is infinite! This seems to be a property of quantized space itself, which is the square of the purest quantized energy field.

AntonioLao · 05-17-2005, 01:50 PM

Quote:

Originally Posted by GUILLE

I think that the moment of equilibrium will be that: a moment. A very short period of time, so small, that there will be no time to distenguish: it will be the smallest "quanta" of time, so time will not pass, I think. Although time will re-activate inmediatelly after.

this seems to agree with inflationary theory of the universe.

Guille · 05-17-2005, 01:51 PM

my answers:

Vacuum is emptiness, so there can't be level of emptiness, can they?

isn't light a property? I think it's stupid to say that the speed of light is constant in vacuum and that it is 300,000km/s because light can't be in a vacuum because the vacuum stops being vacuum when light enters.

Absolute emptiness is by those exact words (it's actually wrong to take things in physics by exact words, like I demostrated with the TOE paradox) is nothing or nothingness. Not even space: not even vacuum space. What is understand by absolute emptiness is vacuum space, which means absence of any kind of property of nature exept of the spatial dimensions.

AntonioLao · 05-17-2005, 02:15 PM

Within the confines of TQS, absolute emptiness is the same as saying that the LIMs are zeros, no local infinitesimal motions, no quantized spaces, no times and the structures of spacetime (if they exist at all) would be uniform and continuous and the universe is that of a steady-state universe.

Guille · 05-17-2005, 02:20 PM

Quote:

Originally Posted by AntonioLao

would be uniform and continuous

Is it any thing to do with the continuose space?

¿Ae=S?

¿absolute emptiness=continuose space?

AntonioLao · 05-17-2005, 02:36 PM

the continuous space of TQS is intimately related to the continuous spacetime curvatures of Einstein's general relativity. And to quantize Einstein's space is only to multiply both sides of his field equations by the factor of light speed.

Guille · 05-17-2005, 02:43 PM

Quote:

Originally Posted by AntonioLao

the continuous space of TQS is intimately related to the continuous spacetime curvatures of Einstein's general relativity. And to quantize Einstein's space is only to multiply both sides of his field equations by the factor of light speed.

Then, why is it so dificult for scientists to unify QM and GR/ER? and create TOE.