That carries no scientific qualifications in any scientific discussion. The best is a PhD license in the science disciplines.Originally Posted by Bogie
That carries no scientific qualifications in any scientific discussion. The best is a PhD license in the science disciplines.Originally Posted by Bogie
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Bogie (07-29-2010)
My friend, you won't be able to stump my on physics questions as long as they are open book. I have a variety of college level physics books and student solutions manuals that I refer to often. I may not have the physics committed to memory but everything in QWC is screened by reference to my library or the internet.
The beginning of absolute comprehension. That's how we learn by asking questions not by providing partially unrelated answers to things that are already been answered completely and scientifically.Originally Posted by labelwench
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Bogie (07-29-2010)
Then refer them. I have all the time in the world to wait for your reply.Originally Posted by Bogie
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
Please quote where I used those terms or quote from the material I posted the lines that bring rise to that question. Also, you didn't read the disclaimer closely enough. Reread the part about other people's theories. If I don't include them specifically I don't defend them.
Again I have to refer you to the disclaimer. Did you interpret all of my many statements in that disclaimer to mean that QWC was science? Please read the part about speculation upon speculation and the fact that I have no proof or test proposed for any of my speculations.
many would agree that scientific discourse (an offensive discourse contrary to defensive ones) is to provide proofs of hypotheses not for others to read between the lines of what anyone wrote or said and try to make sense of them. So far, you have not given any proofs, mathematical or otherwise. What you done is to continue disclaiming your own statements and blaming on others or the internet.
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
It must be or at least close to it. I'm fully aware this is more of a scientific forum. The words you used are all heavily loaded with scientific connotations. So, to be fair, concentrate on the objective scientific meaning and not the implied or personally construed meaning.Originally Posted by Bogie
Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: ¶a(t)·¶r(t)=c²
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