"Sorry! Too Perfect..."

[humanbydefault]

“Sorry! Too perfect to be wrong…”

You all remember this:
1.41421 35623 73095 04880 16887 24209 69807 85696 71875 37694 80731 76679 73799.... No kidding!
Check that out at:

http://en.wikipedia.org/wiki/Square_root_of_2

I will separate each E.R.P.s (fractions made up equal number of decimals representing a secret code for Reality) just as they were presented on the official site:

(41421) (35623) (73095) (04880) (16887) (24209) (69807) (85696) (71875) (37694) (80731) (76679) and… (73799)!

Let’s calculate the “Mirror Value” according to my ‘Object-Image’ conversion procedure:

(41421) = (4 + 1 + 4 + 2 + 1) = 12!
(35623) = (3 + 0 + 1 + 2 + 3) = 9!
(73095) = (2 + 3 + 0 + 4 + 0) = 9!
(04880) = (0 + 4 + 3 + 3 + 0) = 10!
(16887) = (1 + 1 + 3 + 3 + 2) = 10!
(24209) = (2 + 4 + 2 + 0 + 4) = 12!

(69807) = (1 + 4 + 3 + 0 + 2) = 10!
(85696) = (3 + 0 + 1 + 4 + 1) = 9!
(71875) = (2 + 1 + 3 + 2 + 0) = 8!
(37694) = (3 + 2 + 1 + 4 + 4) = 14!
(80731) = (3 + 0 + 2 + 3 + 1) = 9!
(76679) = (2 + 1 + 1 + 2 + 4) = 10!

(73799) = (2 + 3 + 2 + 4 + 4) = 15!

Now! Pay attention to the result obtained by a simple arithmetical addition:

12 + 9 + 9 + 10 + 10 + 12 + 10 + 9 + 8 + 14 + 9 + 10 + 15 = 137!


I challenge any Mathematician (Up to the task) to explain the following numbers using a different argument other than plain Physics!
In an earlier PROOF I demonstrated that a numerical progression reaches ‘perfect symmetry’ in step 6. As you may observe in the quoted analysis of the Square Root of 2 (Picture above) we have symmetry in the first 6 ‘links’:

(41421) = (4 + 1 + 4 + 2 + 1) = 12!
(35623) = (3 + 0 + 1 + 2 + 3) = 9!
(73095) = (2 + 3 + 0 + 4 + 0) = 9!
(04880) = (0 + 4 + 3 + 3 + 0) = 10!
(16887) = (1 + 1 + 3 + 3 + 2) = 10!
(24209) = (2 + 4 + 2 + 0 + 4) = 12!

Two pieces of 9, 10 and 12. Which gives us the total of 62? (The sum of the ‘mirror values’ of all ‘links’)

I want you to pay close attention to the next step!

I will search the number located at the 62th place inside the Table of Primes: It was 293!

So… 62 will have a prime related to it and that is 293.

Let’s do the same operation with the next 6 ‘links’:


(69807) = (1 + 4 + 3 + 0 + 2) = 10!
(85696) = (3 + 0 + 1 + 4 + 1) = 9!
(71875) = (2 + 1 + 3 + 2 + 0) = 8!
(37694) = (3 + 2 + 1 + 4 + 4) = 14!
(80731) = (3 + 0 + 2 + 3 + 1) = 9!
(76679) = (2 + 1 + 1 + 2 + 4) = 10!

Adding up those 6 ‘links’ I obtained 60! Where after searching for its related prime in the Table I found 281!
If I subtract 62 – 60 = 2! But I’m going to use the related Prime Numbers to see what happens…

293 – 281 = 12!

Is everyone still with me? All I’m looking for is the actual “value” of the difference between the two “branches” of the fraction, that’s all!
I did the same ‘search’ in the Table of Primes with 12 and I found its relative Prime and it was 37!

So resuming 12 is the ‘arithmetical magnitude’ or quantitative difference between both “branches” while 37 was the Prime representation of that specific difference.
Please… No confusion when applying the correct terms! [Let’s keep the analysis clean will you?)

Next step (that will amaze you if you understood it) will include the ‘link’ left over from our calculations.

(73799) = (2 + 3 + 2 + 4 + 4) = 15!

If you recall from above I found ALPHA (137) hidden inside the sum of all 13 ‘links’ not just a partial number of them, so I will add the last ‘link’ to the previous “branch”:

60 + 15 = 75! I ‘search’ for the 75th Prime inside the Table and I found 379!

Here we have our first ‘message’! Let’s see it easier…

293 >< 379

Where 293 was the ‘related prime’ of the first “branch” and 379 the ‘related prime’ of the second “branch”.

We know that 7 is the “image” of 2 where the difference is (5) half-cycle ahead in time. Of course the second “branch” is ahead in time by half-cycle and that is the one showing the progression.

But I wasn’t sure about what I found and I had an idea… Let’s subtract 12 (the difference between both “branches”) from the Prime Number related to the second “branch”:

367 – 12 = 367! I did the same ‘search’ in the Table of Primes for 367 and I found that it was the 73rd in the Table.
So! Let me get this straight!

12 = 37! And 367 = 73!

37 >< 73!

Then I was curious to know if 73 was also a Prime and it was! But what I found amazing was that the Prime 73 is the 21st in the Table of the Primes!
The latest result gave me this:

12 >< 21!

This means that there is something going on inside the meaning of 137 that eludes our observation… Assuming the difference between the two “branches” as an ‘inherent perturbation’ [relativistic effect] 137 or ALPHA ‘holds’ a theoretical model for a hidden symmetry despite such effect!

We know that atomic orbitals are exponentially referred to each other as they ‘expand’ in space, could this elemental model of symmetry the one responsible for such structure?

[humanbydefault]

“Still… Too Perfect!”

The following was a blog posted two months ago; let’s paste the entry that day from Integrallife’s site:

(Today is the 13th of June of 2010 and it is 10:30 PM)

“The patterns you’ll see next were the simple product of the multiplication of the square root of 2 by consecutive numbers (i.e. 1, 2, 3, 4, 5, 6, 7, 8, 9 and 10).

Pay close attention to what happens in [8] and [9]:

1. 01.4140 or (014) (140) P= {+3-30} Pt = (0)
2. 02.8230 or [028] (230) P= {+1-10} Pt = (0) >>> Here we have 'Image-Object' Pt= (5)
3. 04.2420 or (042) (420) P= {-2+20} Pt = (0)
4. 05.6560 or (056) (560) P= {+1-10} Pt = (0)
5. 07.0700 or (070) (700) P= {-2+20} Pt = (0)
6. 08.4840 or (084) (840) P= {+1-10} Pt = (0)
7. 09.8980 or [098] (980) P= {-1+10} Pt = (0)
8. 11.3120 Or (113) (120) P= {+2-1+1} Pt = (+2) >>>>>>> (-7)!!! Pt = (5)
9. 12.7260 or (127) (260) P= {0+1+1} Pt = (+2) >>>>>>> (-7)!!!
10. 014.140 or (014) (140) P= {+3-30} Pt = (0)

Easier to see this way:
(113) (120) [(1+1+3) + (1+2+0)] = [(5) + (3)] = 8 [(5) < (3)] = (+2) from right to left*
(127) (260) [(1+2+7) + (2+6+0)] = [(10) + [8] = 18 [(10) < 8] = (+2)

************************************************** **********

It’s so simple, My God!

Let’s ad up the absolute value of the ‘links’ found between (3.) and (8.) since we are trying to look for some sort of a RATIO in between the atomic orbitals... Got it? OK!

3. (042) = (42)!
4. (056) = (06)! Pt = (+5)
5. (070) = (7)!
6. (084) = (34)! Where 8 is the “Image” and 3 is its “Object”
7. [098] = (43)! Where 9 is the “Image” and 4 is its “Object”
8. (113) = (5)!

Now the moment of truth!

Let’s ad up those numbers:
(42) + (6) + (7) + (34) + (43) + (5) = 137! BINGO!

Even under a complete different approach using only the first 4 numbers of the 'Square Root of 2', I reached the same results. If one begin counting from [2.] to [7.]. The result would also come up 137 since point [2.] supplies 5 points. Remember that 8-9 shows here a merge in space-time due to a cancellation of sets (120><-260) while their corresponding ‘links’ on the left deviate in 5 points also.
In point (2.) the “image-object” plays horizontally while in points [8] and [9] they ‘face each other’ vertically on both sets.

This came up naturally from a simple arithmetical operation on 1.414 and was not intentionally “fixed up” to look in some convenient way.

As you see the “mirror values” for each “branch” comes up to 82 >< 55!

Where 82nd Prime was 421 and 55th Prime was 257. Adding up both:

421 + 257 = 678! After an EVEN conversion of 6 and 8 into 1 and 3 we obtain 1, 7 and 3; the same three digits making up for Alpha.

82 = [8 + 2] = 10! And 55 = [5 + 5] = 10!

137 = [1 + 3 + 7] = 11!

421 + 257 = [4 + 2 + 1] + [2 + 0 + 2] After EVEN conversion of 5 and 7 into 0 and 2!

[4 + 2 + 1] + [2 + 2] = 11!

However the most remarkable aspect of this analysis could be resumed by the spontaneous ‘relativistic effect’ derived from the natural appearance of a “two-factor” deviation between both “branches” that coincides with the analysis that introduced this thread… [60 >< 62]

I’m asking you the same question again:

Do they (numbers) speak? Are they trying to communicate something important to us? Can we afford not to listen to them?

You decide!

[Bogie]

What happens when you use pi and go at it both ways?

[humanbydefault]

What happens when you use pi and go at it both ways?

That's an interesting idea Bogie, I have some work done with Pi in the past.

I tell you what: I'll get it and I post it right here so you could check it out. I'll take a closer look at Pi next time, Ok?

HBD