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07-01-2005, 02:28 PM
introducing the ta operator

analogous to Dirac's bra and ket vectors, the del operator has a dual called the ta operator. In 3D Cartesian system, the ta is denoted by

\Delta = \sum \frac{\partial x_i}{\partial} \hat{x_i}

where i=1,2,3

the connection between the del and the ta operator is similar to the covariance and contravariance transformation of tensor analysis.

Traditionally, the outer product of the del operator with a vector is the curl operator. Similarly, the outer product of the ta operator with a vector is the toe operator.

toe \equiv \Delta \times

when del operates on ta is the same as ta operates on del such that

delta = tadel = 1
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07-02-2005, 03:32 PM
although the ta operator uses the same symbol as the difference operator, the ta is a special operator for rank 0 and rank 1 tensors. At first glance, it looks like the inverse of a differential operator. So for now, it could be called temporarily as an integral operator.

http://mathworld.wolfram.com/DifferentialOperator.html

analogous to the gradient vector operator, the tangent vector operator is the ta operator of a scalar, e.g., frequency.

\Delta f = \mathbf{v}

the tangent of frequency is velocity (a vector).

http://mathworld.wolfram.com/Gradient.html

analogous to the divergence operator, the inner product of ta and a vector is called the convergence.

con \equiv \Delta \cdot \mathbf{V}

http://mathworld.wolfram.com/Divergence.html
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07-02-2005, 03:53 PM
furthermore, the inner product of ta by ta is the surface or area operator.

sur \equiv \Delta \cdot \Delta

and the triple products gives a volume operator

vol \equiv \Delta \cdot \Delta \times \Delta

an alternate definition for the ta operator is that it is a length operator, i.e., it changes a scalar into a vector.
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07-10-2005, 03:46 PM
correction to post#1

delta \equiv tadel \equiv -1
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