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phase space to time axis - 08-08-2005, 06:30 PM

Using a phase diagram (a plot of velocity and position), the 2D state of a simple pendulum appears as concentric circles of uniform acceleration around the origin. However, the 3-body dynamical system comprising the Sun, Moon, and Earth has 18 dimensions for its phase space gravity. Furthermore, the phase space of n number of gravitating 3D objects has a total of 6n dimensions. Analogously, quantum mechanics describes the state of an object (e.g. an electron) by four quantum numbers: principal, azimuthal, magnetic, and spin. In order to close the gap of the analogy between celestial mechanics and quantum mechanics, two more quantum numbers must be accounted for making six quantum numbers in all. If one of these quantum number deficits is assigned to the existence of a time axis for each object then there is still one more quantum number unaccounted for. On the other hand, a much better idea is to hypothesize that each object has two time axes: a positive (future) and a negative (past) time axis. With this new idea, the mystery still lies between the interactions of these two time axes such that an object only appears or exists in a state of now referenced as time zero indicating that time does not move at all.

Postulating metrical properties for these time axes solves this mystery. Mathematically, the solutions use the Del operator and the new Ta operator for our simple vector analysis. First, we need to borrow the concept of frequency from wave mechanics and the concept of velocity from particle mechanics (although absolute magnitude of velocity as speed is also a property of waves, it is exclusively a particle property if mass is defined and giving the product as linear momentum of classical mechanics). The following equations assert without any proofs.

\nabla \cdot \mathbf{v} = \nu

\Delta \nu = \mathbf{v}

The first equation states that the divergence of velocity is frequency and the second equation states that the tangent of frequency is velocity. Since metrics are always positive definite, if the length of the positive time axis is greater than zero (e.g. Planck length) then the length of the negative time axis is exactly zero and vice versa (from antiparticles point of view).
  
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08-08-2005, 08:20 PM

I don't think I understand:

Frequency of velocity?
  
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08-10-2005, 08:47 PM

GUILLE,

when frequency is operated by a length vector operator, the result is velocity. Furthermore, I am saying that the divergence of velocity is frequency.
  
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08-11-2005, 04:39 AM

Quote:
Originally Posted by AntonioLao
GUILLE,

when frequency is operated by a length vector operator, the result is velocity. Furthermore, I am saying that the divergence of velocity is frequency.
And what is the convergent of velocity?
  
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08-12-2005, 03:42 PM

Quote:
Originally Posted by GUILLE
And what is the convergent of velocity?
The time rate of change of area.
  
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08-25-2005, 09:11 AM

Quote:
Originally Posted by AntonioLao
The time rate of change of area.
and what are the divergent and convergent of acceleration?
  
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08-25-2005, 12:35 PM

Quote:
Originally Posted by GUILLE
and what are the divergent and convergent of acceleration?
It is a constant square of light speed. The mean curvature of spacetime is zero.
  
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08-28-2005, 07:05 AM

Quote:
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It is a constant square of light speed. The mean curvature of spacetime is zero.
what if it's NOT zero? is the acceleration bigger or smaller than speed of light?
  
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08-28-2005, 02:22 PM

Quote:
Originally Posted by GUILLE
what if it's NOT zero?
Then the true vacuum field (continuous space) is not continuous but quantized and also the universe would have a net electric charge and net linear momentum (either positive or negative).
  
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08-28-2005, 08:42 PM

Everyone here seems to be describing "more of something" but not "of everything".

Please witness "mind-drag" (both "time-line", flaw 2, and "subjective", flaw 5) in vivid action!

"Simply, Everything"
  
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