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10-02-2005, 03:39 PM
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Originally Posted by GUILLE
What is the fundamental theorem of algebra?
Fundamental theorem of algebra states that every polynomial equation having complex coefficients and degree <IMG class=inlineformula height=15 alt=">=1" src="http://mathworld.wolfram.com/images/equations/FundamentalTheoremofAlgebra/inline1.gif" width=24 border=0> has at least one complex root. This theorem was first proven by Gauss. It is equivalent to the statement that a polynomial of degree has values (some of them possibly degenerate) for which . Such values are called polynomial roots. An example of a polynomial with a single root of multiplicity <IMG class=inlineformula height=15 alt=">1" src="http://mathworld.wolfram.com/images/equations/FundamentalTheoremofAlgebra/inline7.gif" width=24 border=0> is , which has as a root of multiplicity 2.
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Time independence: [∂E(g)]²=[∂F(a)×∂r(a)]·[∂F(b)×∂r(b)] and Mass independence: a(tr(t)=c²

Last edited by AntonioLao; 10-03-2005 at 01:04 PM.
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10-03-2005, 01:18 PM
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Why does it impply that complex numbers are algebraicallt closed?
It can be closed by two defined binary operations. Usually, it is addition and multiplication. But first, we need to defined a group, a ring, as well as a field. For the particular type of number we have in mind, it could be closed in a field but not in a ring or in a group. Therefore, a group is a bigger set than the ring or the field. Closed means that whatever you do to the number by the two binary operations, the resulting number belong in the field. If it is outside the field, then it went into the ring, if it is outside the ring, then it went into the group.
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10-03-2005, 01:29 PM
What is smaller the ring or the group?
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10-03-2005, 01:33 PM
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What is smaller the ring or the group?
As far as algebraic properties, the group is more restrictive. But its membership could be more.
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10-03-2005, 01:45 PM
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As far as algebraic properties, the group is more restrictive. But its membership could be more.
Yes, I know that membership is not necesarily related. I meant as algebraic properties.

Now, is there a possibility that a new field of numbers is created/discovered?
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10-03-2005, 01:54 PM
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Now, is there a possibility that a new field of numbers is created/discovered?
The H+ and H- of quantized space couldnt possibly belong to a group or a ring or a field, maybe a ring but they show multiple levels of rings? They dont have any inverses that is to say that their determinants are zeros.
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10-03-2005, 01:59 PM
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The H+ and H- of quantized space couldnt possibly belong to a group or a ring or a field, maybe a ring but they show multiple levels of rings? They dont have any inverses that is to say that their determinants are zeros.
But I mean numerically. Could it be that we arrive to a mathematicla problem that none o fthe numbers that enter in:



And inhacing in the eqution the hypercomplex and hyper real numbers.

Then, if none of those numbers ciould help to solve this problem, could it be that a new field of numbers, like a 3rd dimension (one dimension are real numbers and another dimension are imaginary numbers), coudl it be that it is discovered/created in roder to solve the problem?
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10-03-2005, 02:14 PM
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could it be that a new field of numbers
Similar to the binary system of numbers using 0 and 1. The universal number system use 1 and infinity.
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10-03-2005, 04:14 PM
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Similar to the binary system of numbers using 0 and 1. The universal number system use 1 and infinity.
Doesn't it actually use 0 to infinity?

When I come back from prague I will make a short paper explaining what I mean and why it's so important.
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10-03-2005, 04:35 PM
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Doesn't it actually use 0 to infinity?
Only if space and time axes are connected. I have shown this to be false, that they are simultaneously connected at the exact value of 1 and infinity (not a value by definition).
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